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設這個自然數為了N,兩個完全平方數為a和b(ab-a. 而125=125x1=25x5. ∴b+a=125;b-a=1.或者b+a=25;b-a=5. 解之得:b=63,a=62或b=15,a=10. 故N=a²;-79=62²;-79或10²;-79=3765或21.
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