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證明:∵BF是∠ABC的平分線,∴∠1=∠2,又AB=BC,BF=BF,∴△ABF≌△CBF(SAS),∴FA=FC,∴∠3=∠4,又AF‖DC,∴∠4=∠5,∴∠3=∠5,∴CA是∠DCF的平分線.
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