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甲乙兩車從AB兩地相向而行在距A地60千米處第一次相遇,則甲車行了60千米, 各自到達對方出發地立即返回途中又距A地40千米處相遇,此時甲乙兩車的行程 總和是3倍的全程,即甲車總共行了60*3=180千米 AB相距(180+40)/2=110千米
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