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∵x,y,z為正數 ∴利用柯西不等式 (x+2y+3z)(1/x+2/y+3/z)>=(1+2+3)²; 所以1/x+2/y+3/z>=(1+2+3)²;/(x+2y+3z)=18 所以1/X+2/Y+3/Z最小值為1 8
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