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“數理答疑團”為您解答,希望對你有所幫助.2x²;+8x+3=02(x+2)²;=5x+2=±√10 /2x=-2±√10 /2所以:抛物線y=2x²;+8x+3與x軸有2個公共點公共點的座標是(-2+√10 /2,0)和(-2-√10 /2,0).手機提問的…
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