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f(x)是偶函數,則f(x)=f(-x),則2bx=0,因為在定義域內都成立,則b=0 f(x)是偶函數,則定義域為(a-1,2a)應關於原點對稱,則a-1+2a=0,即a=1/3 所以f(x)=1/3x^2+1
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