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證明:VA=VB,AD=BD⇒VD⊥AB,VO⊥平面ABC,AB⊂平面ABC上⇒VO⊥AB⇒AB⊥平面VCD,CD⊂平面VCD⇒AB⊥CD即CD⊥AB又AD=BD,CD=CD,∠BDC=∠ADC=90°⇒△ADC≌△BDC⇒AC=BC
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