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√3sinα+cosα=2/3, 2*[(√3/2)sinα+(1/2)cosα]=2*(1/3), 2*sin(π/6+α)=2*(1/3) sin(π/6+α)=1/3 cos(π/3+2α)=1-2[sin(π/6+α)]^2=1-2/9=7/9
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