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tanA-tanB=sinA/cosA-sinB/cosB=(sinAcosB-sinBcosA)/(cosAcosB)=sin(A-B)/(cosAcosB)=sin(π/6)/(cosAcosB)=1/(2cosAcosB)=2√3/3=2/√32cosAcosB=√3/2cosAcosB=√3/4
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