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在AB上取中點F,連結EF ∵在梯形ABCD中E、F分別DC、AB的中點 ∴EF=1/2(AD+BC) ∵在Rt△AEB中,F是斜邊AB的中點 ∴FE=1/2AB ∴EF=1/2(AD+BC)=1/2AB ∴AD+BC=AB
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