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二項式公式:(a+b)^n = nC0 a^n + nC1 a^(n-1)*b +…nC(n-1)a*b^(n-1)+ nCn b^n 可見當a=b=1時,多項式係數的和=nC0+nC1+…+nC2+…nC(n-1)+…nCn 所以二項式係數的和=(1+1)^n = 2^n
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