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∵偶數中必含有2這個因數,∴偶數可表示為2n,∴奇數為2n+1或2n-1;同理可得能被5整除的數為5n,4除餘3的數應為4的倍數,再加上3,是4n+3;故答案為2n+1或2n-1;2n;5n;4n+3.
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