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f](sinx)=cos²;x令t=sinx t∈[-1,1]cos²;x=1-sin²;x=1-t²;即f'(t)=1-t²;f'(x)=1-x²;x∈[-1,1]f(x)=∫f'(x)dx=∫1-x²;dx=x-x³;/3+C x∈[-1,1]很高興為您解答,【數學好玩】團…
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