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就是求出 f(x)的n階導數 =(-1)^(n-1)(n-1)!(1+x)^(-n) f^(n)(0)=(-1)^(n-1)(n-1)! 然後代入公式: f(x)=f(0)+f'(0)x+f''(0)/2!*x^2+. 即得最後結果.
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