求證:cosα+√3·sinα=2sin(π/6+α).需要詳細過程謝謝

求證:cosα+√3·sinα=2sin(π/6+α).需要詳細過程謝謝

cosα+√3·sinα
=2*[(1/2)cosα+(√3)sinα/2]
=2*sin[α+(π/6)]