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設公比為q則a2=a1*q,a3=a1*q^2 又an滿足a1a2=1/3,a3=1/9 所以a1^2*q=1/3,a1*q^2=1/9 兩式相乘得,a1^3*q^3=1/27,a1*q=1/3=a2 所以a1=1 故通項公式an=1/3^(n-1)
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