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由題,得n不是偶數,不是3的倍數; 所以n的各數位之和為3k+1或3k+2; 因為n+2是質數,所以n為3k+2; 所以n+1為3k+3,是3的倍數;也是偶數 原式=n+n+2=2(n+1); n+1是二和三的倍數,是六的倍數; 所以原式是12的倍數
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