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設這個式子的和為s 就是s=原式 則同時對兩邊取對數,因為左右均大於0; 則可得s的對數=(2+4+8.+2^(n+1))×2d的對數 對括弧裏的數列等比求和即可 然後再對兩邊同時取指數.把對數符號消掉,就是s了 !為什麼下麵的人copy我的?
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