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1/(2-x)^2=1/(x-2)^2=(x+2)/[(x+2)(x-2)^2] x/(x^2-4)=x/[(x+2)(x-2)]=x(x-2)/[(x+2)(x-2)^2]
x^2-x=1/(x-1)-1/x 1/2(x+1)=0.2(1-1/(x+1))
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