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因為y是純虛數,可設y=bi,(b∈R,且b≠0),原式可整理為(2x-1)+(3-bi)i=bi-i,即(2x-1+b)+3i=(b-1)i,由複數相等的定義可得:2x−1+b=0b−1=3,解得b=4x=−32,故x=−32,y=4i
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