When a power supply is connected with 8 ohm resistor, the current passing through the power supply is 0.1 a

When a power supply is connected with 8 ohm resistor, the current passing through the power supply is 0.1 a

According to Ohm's law I = u / R, the voltage at both ends of the resistance u = I * r, i.e. u = 0.1 * 8 = 0.8V, i.e. the voltage at both ends of the power supply is 0.8V, and the current passing through the power supply is 0.1A. According to Ohm's law, the internal resistance R (internal) = u / I, i.e. R (internal) = 0.8 / 0.1 = 8 Ω
In addition: according to Ohm's law of the whole circuit, I = u (power electromotive force) / R (internal) + R
That is, u (source electromotive force) = I * (R (internal) + R) = 0.1 * (8 + 8) = 1.6V
A: the electromotive force of the power supply is 1.6V and the internal resistance is 8ohm