There are () factors of 120, and the sum of all its factors is ()
120=2^3*3*5
Number of factors = (3 + 1) (1 + 1) (1 + 1) = 16
Sum of factors = (1 + 2 + 4 + 8) (1 + 3) (1 + 5)
=15*4*6=360
120=2^3*3*5
Number of factors = (3 + 1) (1 + 1) (1 + 1) = 16
Sum of factors = (1 + 2 + 4 + 8) (1 + 3) (1 + 5)
=15*4*6=360