In the forest, the hound found a rabbit running 20 meters in front of him, and immediately caught up with him. The hound had a big step. It ran 5 steps, and the rabbit had to run 9 steps, but the rabbit was fast. When the hound ran 2 steps, the rabbit could run 3 steps. How far could the hound run to catch up with the hare?

In the forest, the hound found a rabbit running 20 meters in front of him, and immediately caught up with him. The hound had a big step. It ran 5 steps, and the rabbit had to run 9 steps, but the rabbit was fast. When the hound ran 2 steps, the rabbit could run 3 steps. How far could the hound run to catch up with the hare?

If the hound runs 2 × 5 = 10 steps and the rabbit runs 9 × 2 = 18 steps, the rabbit can only run 3 × 5 = 15 steps in the time of 2 × 5 = 10 steps; then the speed ratio of the hound to the rabbit is 18:15 = 6:5. Suppose the hound runs x meters and the hare runs x-20 meters. X: (x-20) = 6:5 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; &X = 120 A: The Hound runs 120 meters to catch up with the hare