Then 2 + 4 + 6 + 8 +. + 1000 = () Starting from 2, the sum of consecutive n even numbers is 2 + 4 = 6 = 2x3; 2 + 4 + 6 = 12 = 3x4; 2 + 4 + 6 + 8 = 20 = 4x5 Then the sum of N consecutive even numbers should be 2 + 4 + 6 + 8 +. = (). Then 2 + 4 + 6 + 8 +. + 1000 = ()

Then 2 + 4 + 6 + 8 +. + 1000 = () Starting from 2, the sum of consecutive n even numbers is 2 + 4 = 6 = 2x3; 2 + 4 + 6 = 12 = 3x4; 2 + 4 + 6 + 8 = 20 = 4x5 Then the sum of N consecutive even numbers should be 2 + 4 + 6 + 8 +. = (). Then 2 + 4 + 6 + 8 +. + 1000 = ()

The sum of consecutive n even numbers should be 2 + 4 + 6 + 8 +. = (n x (n + 1)), then 2 + 4 + 6 + 8 +. + 1000 = (500x501 = 250500)