A school plans to buy a number of computers. Now we know from two shopping malls that the price of each computer of the same model is 6000 yuan, and there is a certain discount for buying more computers. The preferential condition of shopping mall a is that the first computer will be collected at the original price, and the other computers will be given 25% discount. The preferential condition of shopping mall B is that each computer will be given 20% discount, and the cost of purchasing computers in which shopping mall is less than 1 yuan

A school plans to buy a number of computers. Now we know from two shopping malls that the price of each computer of the same model is 6000 yuan, and there is a certain discount for buying more computers. The preferential condition of shopping mall a is that the first computer will be collected at the original price, and the other computers will be given 25% discount. The preferential condition of shopping mall B is that each computer will be given 20% discount, and the cost of purchasing computers in which shopping mall is less than 1 yuan

According to the meaning of the question: Y1 = 6000 + (1-25%) × 6000 (x-1), that is, Y1 = 4500X + 1500, y2 = (1-20%) × 6000x, that is, y2 = 4800 x, when Y1 < Y2, that is, 4500X + 1500 < 4800 x, the solution is: x > 5, when the number of computers purchased is more than 5, a mall will buy more preferential; when Y1 > Y2, that is, 4500X + 1500