It is known that ab = 8 cm, ad = 12 cm, the area of triangle Abe and triangle ADF are respectively One third of the rectangle ab-cd, find the area of triangle AEF

It is known that ab = 8 cm, ad = 12 cm, the area of triangle Abe and triangle ADF are respectively One third of the rectangle ab-cd, find the area of triangle AEF

Because s triangle Abe = s triangle ADF = S1 / 3 rectangle ABCD
So s triangle AEF = s rectangle - s triangle abe-s triangle ADF = (1-2 / 3) s rectangle = 1 / 3S rectangle
And ab = 8, ad = 12, so s rectangle = 8 * 12 = 96
So s triangle AEF = 1 / 3 * 96 = 32cm square