In △ ABC and △ def, AB / de = BC / EF = Ca / FD = 2 / 3 and the perimeter difference is 15cm, the perimeter of these two triangles is calculated

In △ ABC and △ def, AB / de = BC / EF = Ca / FD = 2 / 3 and the perimeter difference is 15cm, the perimeter of these two triangles is calculated

The circumference of ABC = AB + BC + Ca
The perimeter of △ def = de + EF + FD
The circumference of △ ABC / △ def = (AB + BC + Ca) / (de + EF + FD) = 2 / 3
Circumference of △ def - △ ABC = 15cm
The solution is: the perimeter of △ ABC = 30cm
The circumference of △ def = 45cm