If we know that the image of a linear function y = 2x + A, y = - x + B passes through a (- 2,0) and intersects with y axis at two points B and C respectively, then the area of △ ABC is () A. 4B. 5C. 6D. 7

If we know that the image of a linear function y = 2x + A, y = - x + B passes through a (- 2,0) and intersects with y axis at two points B and C respectively, then the area of △ ABC is () A. 4B. 5C. 6D. 7

Substituting the coordinates of a into the linear function y = 2x + A, y = - x + B, we can get a = 4, B = - 2, then the coordinates of B and C are: B (0,4), C (0, - 2), so the area of △ ABC is: BC × OA △ 2 = 6 × 2 △ 2 = 6