For example, the image of the first-order function y = - 2 / 3x + 2 intersects with the x-axis and y-axis at point AB respectively. With the line AB as the edge, the isosceles triangle ABC is made in the first quadrant, ∠ BAC = 90 ° For example, if there is a point P on the intersection D of AC and y-axis, OA, and the intersection ab of the vertical line of x-axis, AC is at two points m and N, if Mn = 1 / 3bd, the P coordinate is?

For example, the image of the first-order function y = - 2 / 3x + 2 intersects with the x-axis and y-axis at point AB respectively. With the line AB as the edge, the isosceles triangle ABC is made in the first quadrant, ∠ BAC = 90 ° For example, if there is a point P on the intersection D of AC and y-axis, OA, and the intersection ab of the vertical line of x-axis, AC is at two points m and N, if Mn = 1 / 3bd, the P coordinate is?

First, find out the coordinates of a and B,
The point of intersection a 0 = - 2 / 3x + 2 with X axis, the solution is x = 3, that is, the coordinate of point a is (3,0)
The point of intersection with y axis b y = - 2 / 3 * 0 + 2, the solution is y = 2, that is, the coordinate of point B is (0,2)
If the length of AB is equal to the sum of (3-0) ^ 2 + (2-0) ^ 2, then AB = root 13
And because AC is perpendicular to AB, the slope of the line AC is equal to 3 / 2
So the analytical formula of the straight line passing through two points is y = 3 / 2x + 3
If the sum of (3 / 2x + 3-3) ^ 2 + (x-0) ^ 2 is equal to 13, the solution is x = 2, or x = - 2;
That is, the coordinates of point C are (2,6) or (- 2,0)
The following questions are confusing