It is known that be is the bisector of the inner angle of triangle ABC and CE is the bisector of the outer angle of triangle ABC Add a reason after each step
Method 1: ∵ ACD is the outer angle of △ ABC, ∵ ACD = ∵ a + ∵ ABC, ∵ be is the angular bisector of ABC, ∵ EBC = 1 / 2 & nbsp; ∵ ABC ∵ CE is the angular bisector of ∵ ACD, ∵ ECD = ∵ ace = 1 / 2 & nbsp; ∵ ACD, ∵ EBC + ∵ ECB = 1 / 2 & nbsp; ∵ ABC + (∵ ACB + ∵ ACE)) = 1 / 2 & nbsp