It is known that be is the bisector of the inner angle of triangle ABC and CE is the bisector of the outer angle of triangle ABC Add a reason after each step

It is known that be is the bisector of the inner angle of triangle ABC and CE is the bisector of the outer angle of triangle ABC Add a reason after each step

Method 1: ∵ ACD is the outer angle of △ ABC, ∵ ACD = ∵ a + ∵ ABC, ∵ be is the angular bisector of ABC, ∵ EBC = 1 / 2 & nbsp; ∵ ABC ∵ CE is the angular bisector of ∵ ACD, ∵ ECD = ∵ ace = 1 / 2 & nbsp; ∵ ACD, ∵ EBC + ∵ ECB = 1 / 2 & nbsp; ∵ ABC + (∵ ACB + ∵ ACE)) = 1 / 2 & nbsp