There is a RT triangle ABC, BC = 2, AC = radical 3, ab = 1. Put it in the rectangular coordinate system, BC is on the x-axis, and the right angle vertex is on the y = radical 3 / X image, and find the coordinates of point C

There is a RT triangle ABC, BC = 2, AC = radical 3, ab = 1. Put it in the rectangular coordinate system, BC is on the x-axis, and the right angle vertex is on the y = radical 3 / X image, and find the coordinates of point C

(2.5, 0)
According to the fact that the area of the same triangle is equal, so abxac = bcxad, ad is the height on the side of BC, we can get ad = root 3 / 2, a is on y = root 3 / x, so the coordinate of point a is (2, root 3 / 2)
Because the angle ABC = 30 degrees, BD = 1.5, then DC = 0.5, so OC = od + DC = 2 + 0.5 = 2.5