It is known that the triangle ABC is an isosceles triangle, in which the length of one side is 10 and the length of the other side is a quadratic equation of one variable with respect to X The square of X - (2k + 2) the square of X + K + 2K = 0

It is known that the triangle ABC is an isosceles triangle, in which the length of one side is 10 and the length of the other side is a quadratic equation of one variable with respect to X The square of X - (2k + 2) the square of X + K + 2K = 0

X ^ 2 - (2k + 2) x + K ^ 2 + 2K = 0 by cross multiplication: (x-k-2) * (x-k) = 0 x = K + 2 or K (1) if the waist is 10, when K + 2 = 10, k = 8, the length of three sides of the triangle is 10,10,8, so that the sum of two sides is greater than the third side, and the difference between two sides is less than the third side