A calculation problem is simplified first, then evaluated -2 (mn-3m & sup2;) - {M & sup2; - 5 (mn-m & sup2;) + 2Mn}, where M = 1, n = 2

A calculation problem is simplified first, then evaluated -2 (mn-3m & sup2;) - {M & sup2; - 5 (mn-m & sup2;) + 2Mn}, where M = 1, n = 2

Fat kapok pre simplification: - 2 (mn-3m & sup2;) - [M & sup2; - 5 (mn-m & sup2;) + 2Mn] = - 2Mn + 6m & sup2; - (M & sup2; - 5MN + 5m & sup2; + 2Mn) = - 2Mn + 6m & sup2; - (6m & sup2; - 3MN) = - 2Mn + 6m & sup2; - 6m & sup2; + 3MN = Mn