The object from the top of the inclined plane from static to the bottom of the inclined plane, the first 3 seconds after the displacement S1 S2 S1 + S2 = 1.2m S1: S2 = 3:7, calculate the length of the inclined plane

The object from the top of the inclined plane from static to the bottom of the inclined plane, the first 3 seconds after the displacement S1 S2 S1 + S2 = 1.2m S1: S2 = 3:7, calculate the length of the inclined plane

From S1 + S2 = 1.2m, S1: S2 = 3:7, we can get S1 = 0.36M, S2 = 0.84M. According to the displacement ratio of adjacent equal time interval in uniform speed linear motion is 1:3:5:1 (2n-1) it can be seen that the displacement in the nth time interval is equal to (2n-1) times of the displacement in the first second, 7 = 3 × (2n-1), n = 5 / 3