When an object moves in a straight line with uniform deceleration, the initial velocity is 12 meters per second, the acceleration is 2 meters per second, and the displacement of the object in a second is 6 meters. How far can it move after that Why can't we do this According to v = V0 + at, we get 0 = 12 + (- 2) t, t = 6S is to calculate how long he stops Then use x = v0t + 1 / 2at2 to find out x = 36-6 = 30. Why can't we do this? Find out the reason and correct method

When an object moves in a straight line with uniform deceleration, the initial velocity is 12 meters per second, the acceleration is 2 meters per second, and the displacement of the object in a second is 6 meters. How far can it move after that Why can't we do this According to v = V0 + at, we get 0 = 12 + (- 2) t, t = 6S is to calculate how long he stops Then use x = v0t + 1 / 2at2 to find out x = 36-6 = 30. Why can't we do this? Find out the reason and correct method

Because you do this, the default is that 6 meters in one second is the displacement in the first second, but at the beginning, the displacement in one second is not 6 meters, but a little larger, 11 meters in the first second