Given 4x + 3Y = 2 (x > 0, Y > 0), then the maximum value of XY is equal to

Given 4x + 3Y = 2 (x > 0, Y > 0), then the maximum value of XY is equal to

x. Y > 0,2 = 4x + 3Y ≥ (4 √ 3) √ (XY) = = = > XY ≤ 1 / 12. The equal sign is obtained only when x = 1 / 4, y = 1 / 3