It is proved that: (1) the value of - (x square) + 6x-10 is always less than zero; (2) the value of 4 (x square) - 12x + 10 is always greater than zero

It is proved that: (1) the value of - (x square) + 6x-10 is always less than zero; (2) the value of 4 (x square) - 12x + 10 is always greater than zero

1. - X & # 178; + 6x-9-1 = - (x-3) & # 178; - 1 ᙽ (x-3) & # 178; must be greater than 0, then - (x-3) & # 178; must be less than 0, that is - X & # 178; + 6x-9-1 = - (x-3) & # 178; - 1 is always less than 02.4x & # 178; - 12x + 10 = 4x & # 178; - 12x + 9 + 1 = (2x-3) & # 178; + 1 is always greater than 0