Let a = {(x, y) | y = 2x-1, X ∈ positive natural number}, B = {(x, y) | y = ax ^ 2-ax + A, X ∈ positive natural number}, ask whether there is a non-zero real number a, let a ∩ B be If there is a single element set, find out the value of A. if not, explain the reason

Let a = {(x, y) | y = 2x-1, X ∈ positive natural number}, B = {(x, y) | y = ax ^ 2-ax + A, X ∈ positive natural number}, ask whether there is a non-zero real number a, let a ∩ B be If there is a single element set, find out the value of A. if not, explain the reason

Two equations together... And then move to one side... Because this is a quadratic equation with one variable. If there is a solution and only one... Then there is only a discriminant... If the discriminant is equal to 0, it is better to solve it directly