If we know that set a satisfies the following conditions: when p ∈ a, there is always (- 1 / P + 1) ∈ A. if we know that 2 belongs to a, then the product of all elements in set a is equal to

If we know that set a satisfies the following conditions: when p ∈ a, there is always (- 1 / P + 1) ∈ A. if we know that 2 belongs to a, then the product of all elements in set a is equal to

From P ∈ a, - 1 / P + 1 ∈ a can be obtained
-1 / P + 1 ∈ a, namely (p-1) / P ∈ a = > - P / (p-1) + 1 ∈ a, namely 1 / (1-p) ∈ a
From 1 / (1-p) ∈ a, we can know - (1-p) / 1 + 1 ∈ a, that is p ∈ a
Therefore, the value of set a is {P, - 1 / P + 1,1 / (1-p)}
When p = 2, a is {2, - 1 / 3, - 1}
The product of all the elements in a is 2 / 3