Root test method for solving cubic equation x ^ 3-3x ^ 2 + 4x = 2 Factorization, look at the constant term, - 2 = - 2 * 1 or - 1 * 2 Substituting - 1, - 2, 1 and 2 respectively, we find that the equation holds when y = 1 Then it contains the factor (Y-1) How to find the latter factor?

Root test method for solving cubic equation x ^ 3-3x ^ 2 + 4x = 2 Factorization, look at the constant term, - 2 = - 2 * 1 or - 1 * 2 Substituting - 1, - 2, 1 and 2 respectively, we find that the equation holds when y = 1 Then it contains the factor (Y-1) How to find the latter factor?

Deal with the original formula
x^3-3x^2+4x-2
=x^3-x^2_ 2x^2+2x+2x-2
=x^2(x-1)-2x(x-2)+2(x-1)
=(x-1)(x^2-2x+2)
Is to open the term to get together, of course, you can also vertical division
Later, we use the root formula to solve the problem