For any x1, X2 (x1 ≠ x2) in the definition field of function f (x) = lgx, the following conclusion is obtained f((x1+x2)/2)

For any x1, X2 (x1 ≠ x2) in the definition field of function f (x) = lgx, the following conclusion is obtained f((x1+x2)/2)

1, the second derivative is negative, so it is a convex function, so f ((x1 + x2) / 2) > = f (x1) + F (x2) / 2
2. Direct calculation is also very simple. Let one of X1 and X2 be a variable, and then there are many ways to solve the problem of monotonicity of function
The second is recommended