If the function f (x) = a + 2 / (2 ^ x-1) is an odd function in its domain, then the value of the real number a

If the function f (x) = a + 2 / (2 ^ x-1) is an odd function in its domain, then the value of the real number a

The simplest method is the copy method, because it is an odd function, so f (1) = a + 2, f (- 1) = A-4, so 4-A = a + 2, so a = 1. To calculate, use the definition f (x) = - f (- x) if the function is f (x) = a + 2 / (2 ^ x-1) is my answer. If the function is a + 2 / 2 ^ X-1, then f (0) = a + 2-1 = 0, so a = - 1