The known function (x) = sin (2x Pai / 6) + cos ^ 2x. (1). If f (x) = 1, find the value of sinacosa. (2) Known function (x) = sin (2x Pai / 6) + cos ^ 2x (1) If f (x) = 1, find the value of sinacosa (2) How to find the monotone increasing interval of function f (x)?

The known function (x) = sin (2x Pai / 6) + cos ^ 2x. (1). If f (x) = 1, find the value of sinacosa. (2) Known function (x) = sin (2x Pai / 6) + cos ^ 2x (1) If f (x) = 1, find the value of sinacosa (2) How to find the monotone increasing interval of function f (x)?

(1) Simplify f (x), that is, f (x) = (2 / 2 root 3) sin2x - (1 / 2) cos2x + (1 + cos2x) / 2 = (2 / 2 root 3) sin2x + 1 / 2. If f (x) = 1, that is, (2 / 2 root 3) * 2 * sinxcosx = 1 / 2, so sinxcosx = 1 / (2 root 3)
(2) According to the simplified function self seeking