Limit LIM (sinx-x) / x ^ 3 = LIM (- x ^ 3 / 6 / x ^ 3) = - 1 / 6, where X - > 0 - how to deduce these two steps? Principle and explanation Limit LIM (sinx-x) / x ^ 3 = LIM (- x ^ 3 / 6 / x ^ 3) = - 1 / 6, where X - > 0 - how to deduce these two steps? Principle and explanation X ^ 3 is the third power of X

Limit LIM (sinx-x) / x ^ 3 = LIM (- x ^ 3 / 6 / x ^ 3) = - 1 / 6, where X - > 0 - how to deduce these two steps? Principle and explanation Limit LIM (sinx-x) / x ^ 3 = LIM (- x ^ 3 / 6 / x ^ 3) = - 1 / 6, where X - > 0 - how to deduce these two steps? Principle and explanation X ^ 3 is the third power of X

It should be calculated as follows: LIM (sinx-x) / x ^ 3 = LIM (cosx-1) / 3x ^ 2 = LIM (- x ^ 2 / 2 / 3x ^ 2) = - 1 / 6;
The law of lobita and the limit are equal: LIM (cosx-1) ~ - x ^ 2 / 2