A problem of periodic function, Given that the domain of definition of function y = f (x) is r, f (x + 2011) = f (x + 2010) + F (x + 2013) holds for any real number X. if f (1) + F (2) = 1 and f (1) + F (2) + +If f (2013) = 0, then f (2007) =?

A problem of periodic function, Given that the domain of definition of function y = f (x) is r, f (x + 2011) = f (x + 2010) + F (x + 2013) holds for any real number X. if f (1) + F (2) = 1 and f (1) + F (2) + +If f (2013) = 0, then f (2007) =?

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