11 + n can be divided by n ^ 2 + 9n-2 to find the value of natural number n

11 + n can be divided by n ^ 2 + 9n-2 to find the value of natural number n

(n ^ 2 + 9n-2) / (n + 11) = (n ^ 2 + 11n-2n-2) / (n + 11) = [n (n + 11) - 2n-2] / (n + 11) = n-2 (n + 1) / (n + 11) = n-2 (n + 11-10) / (n + 11) = (n-2) + 20 / (n + 11), so n + 11 is a divisor of 20, and N is a natural number, so in the divisor of N + 11 > = 1120, only 20 is greater than or equal to 11, and N + 11 = 20n = 9