The object with mass m = 2kg is still on the horizontal plane, and the dynamic friction coefficient between them is μ = 0.5. Now, the force F, f = 10N, θ = 37 ° as shown in the figure is applied to the object. After t = 10s, the force F is removed, and after a period of time, the object is still again (1) The acceleration of an object when accelerating (2) what is the maximum velocity in the process of the object moving (3) what is the total displacement of the object moving? (g = 10m / S2)

The object with mass m = 2kg is still on the horizontal plane, and the dynamic friction coefficient between them is μ = 0.5. Now, the force F, f = 10N, θ = 37 ° as shown in the figure is applied to the object. After t = 10s, the force F is removed, and after a period of time, the object is still again (1) The acceleration of an object when accelerating (2) what is the maximum velocity in the process of the object moving (3) what is the total displacement of the object moving? (g = 10m / S2)

(1) F sin θ + N1 = Mg & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; fcos θ - F1 = MA1 & nbsp; & nbsp; & nbsp; F1 = μ n1s1 = 12a1t12 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; substituting into the numerical value, A1 = 0.5m/s2, direction: horizontal right (2) v = 5m / s due to v = a1t1, (3) F2 = μ mg = ma2 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; after f is removed; 2a2s2 = V2 total displacement: S = S1 + S2 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; s = 27.5m A: the acceleration of the object is 0.5m/s2 & nbsp; & nbsp; direction: horizontal to right; the maximum velocity of the object is 5m / S; the total displacement of the object is 27.5m