As shown in the figure, the bullet with mass m hits the wooden block m resting on a smooth horizontal plane at the speed V0, and the average resistance of the bullet in the wooden block is f, The velocity of the bullet is v 1 after shooting through the block

As shown in the figure, the bullet with mass m hits the wooden block m resting on a smooth horizontal plane at the speed V0, and the average resistance of the bullet in the wooden block is f, The velocity of the bullet is v 1 after shooting through the block

The horizontal momentum of bullet and block is conserved. MV0 = MV1 + MV, block velocity v = m (v0-v1) / m
The mechanical energy loss of the system is: 0.5m (V0 ^ 2-v1 ^ 2) - 0.5mv ^ 2 = 0.5m (V0 ^ 2-v1 ^ 2) - 0.5m ^ 2 * (v0-v1) ^ 2gm