The bus departs from the station and runs at a speed of 4 m / s along the straight road at a constant speed. Two seconds later, a motorcycle departs from the same station to catch up at a constant speed The acceleration is 3m / S & sup2;, Q 【1】 How long does it take for the motorcycle to catch up with the car? 【2】 How far is it from the starting point when the motorcycle catches up with the car

The bus departs from the station and runs at a speed of 4 m / s along the straight road at a constant speed. Two seconds later, a motorcycle departs from the same station to catch up at a constant speed The acceleration is 3m / S & sup2;, Q 【1】 How long does it take for the motorcycle to catch up with the car? 【2】 How far is it from the starting point when the motorcycle catches up with the car

Set T seconds to catch up
Distance of car = distance of motorcycle
4 (T + 2) = 1 / 2at ^ 2, 4 (T + 2) = 1 / 2 * 3T ^ 2, and T = 4 by solving the equation
So I caught up in four seconds
Distance from departure = distance of motorcycle s = 1 / 2 * 3 * T ^ 2 = 1 / 2 * 3 * 16 = 24
Note: ^ denotes superscript