The motorcycle starts from standstill, runs for a distance with the acceleration of A1 = 1m / S2, then makes a constant speed movement, and then makes a constant deceleration movement with the acceleration of A2 = - 4m / S2 until it stops. The motorcycle has walked 1440m in total and lasted for 100s. The maximum speed of the motorcycle in this process is calculated

The motorcycle starts from standstill, runs for a distance with the acceleration of A1 = 1m / S2, then makes a constant speed movement, and then makes a constant deceleration movement with the acceleration of A2 = - 4m / S2 until it stops. The motorcycle has walked 1440m in total and lasted for 100s. The maximum speed of the motorcycle in this process is calculated

The whole motion process is divided into three stages: uniform acceleration, uniform velocity and uniform deceleration. Let the time used be T1, T2 and T3 respectively, then the maximum velocity VM = a1t1, the average velocity of acceleration process is vm2, the velocity of uniform velocity process is VM all the time, and the displacement of the whole process used in deceleration phase is vm2t1 + vmt2 + vm2t3 = 1440 ① According to the speed time relationship VM = a1t1 = a2t3, the solution is: T1 = VMA1, ② T3 = vma2, ③ T2 = 130-t1-t3, ④ by substituting ①, ②, ④ into the data solution: VM = 16m / s. A: the maximum speed of motorcycle in this process is 16m / s